49x^2=35

Solution for 49x^2=35 equation:

49x^2=35

We move all terms to the left:

49x^2-(35)=0

a = 49; b = 0; c = -35;
Δ = b2-4ac
Δ = 02-4·49·(-35)
Δ = 6860
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6860}=\sqrt{196*35}=\sqrt{196}*\sqrt{35}=14\sqrt{35}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-14\sqrt{35}}{2*49}=\frac{0-14\sqrt{35}}{98}
=-\frac{14\sqrt{35}}{98}
=-\frac{\sqrt{35}}{7}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+14\sqrt{35}}{2*49}=\frac{0+14\sqrt{35}}{98}
=\frac{14\sqrt{35}}{98}
=\frac{\sqrt{35}}{7}
$